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fix: conditionally render pin button based on app ID

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ousugo 2025-01-20 00:03:51 +08:00 committed by 亢奋猫
parent c0e25879e5
commit 725f81c165
1 changed files with 6 additions and 3 deletions
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9
src/renderer/src/components/MinApp/index.tsx
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@ -31,6 +31,7 @@ const PopupContainer: React.FC<Props> = ({ app, resolve }) => {
useBridge()
const canOpenExternalLink = app.url.startsWith('http://') || app.url.startsWith('https://')
const canPinned = !!app.id
const onClose = async (_delay = 0.3) => {
setOpen(false)
@ -63,9 +64,11 @@ const PopupContainer: React.FC<Props> = ({ app, resolve }) => {
<Button onClick={onReload}>
<ReloadOutlined />
</Button>
<Button onClick={onTogglePin} className={isPinned ? 'pinned' : ''}>
<PushpinOutlined style={{ fontSize: 16 }} />
</Button>
{canPinned && (
<Button onClick={onTogglePin} className={isPinned ? 'pinned' : ''}>
<PushpinOutlined style={{ fontSize: 16 }} />
</Button>
)}
{canOpenExternalLink && (
<Button onClick={onOpenLink}>
<ExportOutlined />